1 X 1 X 2 1 X 2 X 3 1 X 3 X 4 1 6

Apply the distributive property by multiplying each term of x 1 by each term of x.

1 x 1 x 2 1 x 2 x 3 1 x 3 x 4 1 6. As n approaches infinity the sum approaches 1 1 x. A 7 b 2 5 c 6 d 3 5 at what time between 12 and 1 will be hands of a clock be in the same straight line but not together a 35 minutes past 12 b 54 minutes past 12. What are you looking for. Finding on the table we are able to verify that as our x values advance by potential of a million our y values are showing suitable squares.

X 1 x 2 x 3 x 4 apply the distributive property by multiplying each term of x 1 by each term of x 2. 1 6 1 2 2 3. 3x 5 x 3x 2 6 x. Of the subsequent x fee.

1 1 2 x 1 x 2 x 2 x 3 3 1 1 1. In spite of the undeniable fact which you in addition to mght observe that the y values are showing the sq. X 1 2 3 is not possible because of divison against zero. While x is two y 9 that s the sq.

Observe while x is a million y 4 that s the sq. This is a geometric series with first term 1 and common ratio x. 1x n 1 x 1 1 x n 1 x note. Take the lcm of the denominators x 1 x 2 x 3 x 4 divide the lcm by the denominator of each term and multiply the result with the numerator of the respective term.

X 1 2 x 2 x 2 x 1 x 1 2x 4 x 3x 2 3x 5 x 3x 2 now the equation is. But because this is a quadratic x equatation there exist a second answer.